4x^2+7x-84=0

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Solution for 4x^2+7x-84=0 equation:



4x^2+7x-84=0
a = 4; b = 7; c = -84;
Δ = b2-4ac
Δ = 72-4·4·(-84)
Δ = 1393
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{1393}}{2*4}=\frac{-7-\sqrt{1393}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{1393}}{2*4}=\frac{-7+\sqrt{1393}}{8} $

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